Datasheet

12
474
a
1
2
3
J = m
1
· + m
2
·
a
2
2
3
a
b
J = ( )
2
J
B
+ J
B
a
2
12
J = m ·
a
2
12
J = m ·
4a
1
2
+ b
2
12
J = m
1
· + m
2
·
4a
2
2
+ b
2
12
a
2
+ b
2
12
J = m ·
r
2
2
J = m ·
2r
2
5
J = m ·
r
2
4
J = m ·
a
1
2
3
J = m
1
· + m
2
· a
2
2
+ K
2r
2
5
K = m ·
Subject to change
SI UNITS, SYMBOLS AND DIMENSIONING
Mass moment of inertia
When dimensioning a rotary actuator you must, in addition to
necessary torque, also consider the load’s mass moment of inertia.
For your aid, please nd the formulas below (dimensions in meters).
1. Thin axle,
excentrically suspended
3. Thin rectangular plate,
on edge and centered
5. Thin rectangular plate,
lying down and centered
7. Sphere (ball), centered
2. Thin axle,
centered suspension
4. Thin rectangular plate,
lying down and
excentrically suspended
6. Thin disc,
lying down and centered
8. Thin disc,
on edge and centered
9. Thin axle with mass
When m
2
is spherical, K equals,
as in case 7:
10. Transmission
First calculate mass moment
of inertia for gears A and B (as
in case 6) and then:
No of teeth = a
No of teeth = b
If the axle is carrying a disc, calculate K as in case 6 or 8.
a
2
a
1
a
a
1
a
2
b
a
b
a
b
r
r
r
a
2
r
a
1
m
1
m
2
(A)
(B)